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Mathematics 7 Online
OpenStudy (kj4uts):

Suppose a triangle has two sides of length 2 and 3 and that the angle between those two sides is pi/3. What is the length of the third side of the triangle? Please explain. Thank you!

OpenStudy (kj4uts):

OpenStudy (anonymous):

Law of Cosines

OpenStudy (anonymous):

a^2 + b^2 - 2abcos(C) = c^2

OpenStudy (anonymous):

a and b are the given sides. C is the angle between them. c is the length of the side you are looking for

Directrix (directrix):

x^2 = 2^2 + 3^2 - 2*2*3* cos (60 degrees) Solve for x.

Directrix (directrix):

Copy and paste this: x^2 = 2^2 + 3^2 - 2*2*3* cos (60 degrees) Enter it here: http://www.wolframalpha.com/ Post what x cranks out to be. I got one of your options but you need to check. @KJ4UTS

OpenStudy (kj4uts):

@Directrix I got x^2= 7. I also found someone else that asked this question: http://openstudy.com/study#/updates/4e45b0170b8b3609c723c5d1 But the person who answered it used x^2=2^2+3^2-2*3*2*(cos pi/3)

OpenStudy (anonymous):

pi/3 radians = 60 degrees

OpenStudy (kj4uts):

oh ok

Directrix (directrix):

Solve for x: x^2= 7

Directrix (directrix):

@KJ4UTS What is x? If you follow my instructions on using Wolframalpha and scroll down, you'll see the answer.

OpenStudy (kj4uts):

I see square root 7

Directrix (directrix):

There it is, your answer.

OpenStudy (kj4uts):

oh ok thanks again that Wolframalpha looks really helpful.

Directrix (directrix):

You are welcome.

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