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Algebra 9 Online
OpenStudy (anonymous):

Find the missing term

OpenStudy (anonymous):

mathslover (mathslover):

You have : \(y = 1 + i\) Subtract 1 both sides, you get : \(\color{red}{ y - 1 } = i\) Cube both sides and simplify further, you will get the required term. \(\color{red}{ (y-1)^3} = -i\) Note: \(i^3 = i \times i \times i = i^2 \times i = -1 \times i = -i\)

OpenStudy (anonymous):

\[(1+i)^{3}=?\]

OpenStudy (radar):

You need to know what y^2 is. (1+i)^2. Can you calculate that?

OpenStudy (anonymous):

-3y+1?

OpenStudy (anonymous):

Is that my final answer?

OpenStudy (radar):

After getting that and making a record of that, calculate y^3.

OpenStudy (ribhu):

no check please

OpenStudy (radar):

Substitute those into y^3 - 3y^2 + (?) -1 = i and then you will be able to determine what should go into the parenthesis.

OpenStudy (anonymous):

So 3y will be my final answer

OpenStudy (radar):

I will start with showing you how to get y^2|dw:1424710402393:dw|

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