Consider the chemical equation.

CuCl2 + 2NaNO3 mc023-1.jpg Cu(NO3)2 + 2NaCl

What is the percent yield of NaCl if 31.0 g of CuCl2 reacts with excess NaNO3 to produce 21.2 g of NaCl?

Question

Consider the chemical equation.


CuCl2 + 2NaNO3 mc023-1.jpg Cu(NO3)2 + 2NaCl


What is the percent yield of NaCl if 31.0 g of CuCl2 reacts with excess NaNO3 to produce 21.2 g of NaCl?

welshfella · Answer

CuCL2 = 63.55 + 2*35.45 = 134.45
2 Na Cl = 2(23 + 35.450 = 116.90

welshfella · Answer

so 134.45 of CuCl2 should produce 116.90  gm of NaCL  if the yield is 100%
  31g  should produce  116.9 * 31
                                     --------    g  of NACL  = X g
                                         134.45

% yield will   21.2  * 100
                    ---------
                           X