Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (love_to_love_you):

Please help! Will fan and medal!

OpenStudy (love_to_love_you):

Write a polynomial function with rational coeffiecients so that P(x)=0 has the given roots. Show all work. 11-2i and 8+13i

OpenStudy (love_to_love_you):

@mathmath333

OpenStudy (love_to_love_you):

@mustafa2014

OpenStudy (love_to_love_you):

@jigglypuff314

OpenStudy (anonymous):

same idea

OpenStudy (anonymous):

(x-(11-2i))(x-(8+13i))=0

OpenStudy (anonymous):

because 11-2i and 8+13i roots of this polynomial

OpenStudy (love_to_love_you):

ohh.

OpenStudy (love_to_love_you):

well I don't have to do anything else in order to get the answer? its just that?

OpenStudy (mathmath333):

you are given that all coefficients are rational ?

OpenStudy (love_to_love_you):

yes

OpenStudy (mathmath333):

\(\large \begin{align} \color{black}{\left(x-(11-2i )\right)\times \left(x-( 8+13i)\right) =0}\end{align}\) does'nt gives rational coefficients http://www.wolframalpha.com/input/?i=%28x-%2811-2i+%29%29*%28x-%28+8%2B13i%29%29%3D because the complex numbers always comes in pairs so ur right answer would be \(\large \begin{align} \color{black}{\left(x-(11-2i) \right)\left(x-(11+2i )\right)\left( x-(8+13i) \right)\left(x-(8-13i)\right)=0 }\end{align}\) http://www.wolframalpha.com/input/?i=%28x-%2811-2i%29+%29*%28x-%2811%2B2i+%29%29*%28+x-%288%2B13i%29+%29*%28x-%288-13i%29%29%3D

OpenStudy (anonymous):

i think there are somthing wrong

OpenStudy (love_to_love_you):

wait so which one is right?

OpenStudy (anonymous):

second one

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!