Question

y=(x^2+3x)/2x Okay so i need to find the y-intercept of this problem and I know that I plug zero in for x, but the denominator is a domain error, but my question is can I factor an x out of the numerator and simplify so that my new equation would be (x+3)/2 and my denominator would not equal zero, or is this not allowed?

Answer 1

you are given:\[y=\frac{x^2+3x}{2x}=\frac{x(x+3)}{2x}\]notice how \(x\) is a common factor in the numerator and the denominator. So you can find the limit of this expression as \(x\) tends to zero by cancelling out these \(x\)'s first

Answer 2

I'm soo confused and i don't think that my teacher wants us to use limits she just wants us to find the intercepts...

Answer 3

if you haven't been taught limits yet, then first simplify the expression by cancelling the \(x\)'s and then substitute \(x=0\) to get the \(y\) intercept.

Answer 4

so i can manipulate the equation and get (0,3/2)?

Answer 5

yes :)

Answer 6

omg thanks so much

Answer 7

yw :)