Question

An official major league baseball has a mass of 0.14 kg. A pitcher throws a 40 m/s fastball which is hit by the batter straight back up the middle at a speed of 46 m/s.
A) What is the change in momentum of the ball during the collision with the bat?
B) If this collision occurs during a time of 0.012 seconds, what is the average force exerted by the bat on the ball?

Answer 1

Given m=0.14kg
u=40m/s
v=-46m/s

Answer 2

A)
Change in momentum=mv-mu=?

Answer 3

B)
Force F=(mv-mu)/t=?

Answer 4

Response plz!!!