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OpenStudy (anonymous):
on a normal distribution with a mean of 100 and a standard deviation of 17 what percentage of cases will fall between 84 and 93?
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OpenStudy (tkhunny):
Calculate the z-scores.
OpenStudy (anonymous):
\[z=(100-84)\div17 <x <(100-93)\div17\]
OpenStudy (anonymous):
then plug into the z tables!
OpenStudy (anonymous):
in order to find %
OpenStudy (tkhunny):
Technically, that would be 84-100 and 93-100, but the answer is still good due to symmetry.
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