Question

The chance of David winning a game is 1/3. If he plays five times, what is
the probability that he will win exactly once?

Answer 1

hi!!

Answer 2

wins once, loses 4 times

Answer 3

there are 5 different ways he can win once exactly
first, second, third, fourth, fifth time
so
\[5\times \left(\frac{1}{3}\right)\left(\frac{2}{3}\right)^4\]

Answer 4

So this is a Dependent Event

Answer 5

My professor sucks on showing how to properly choose how to set the problem up. The answer is 80/243. Thanks