Will fan and medal to the correct answer!
Find the \[a ^{2}...a ^{3}...a ^{4}...\]
MATHMATEEEE HIIIII
www.Mathway.com
how could that website work out this problem
it will find it for you if you type in this sequence/equation ;) Hope this helps. Also Wolfram Alpha but thats more complex to use
let me try it there for u :)
it doesnt work when you get to the 3,
ya i just found that out ok wait again :P
the answers are A. = 5,7,9 B. = 7,9,11
C. = 5,8,11
D. = 3,9,21
tha being in the form of a2 a3 a4
ohhh ok then wait :P
see it doenst work for crap like this
Alright let me see, step by step with each of these answers ok so A. = 5,7,9 B. = 7,9,11 C. = 5,8,11 D. = 3,9,21 remember A1=0 so if you are going by a1, a2,a3,a4 then its 0,5,7,9 0,7,9,11 0,5,8,11 0,3,9,21 ryt? do you understand so far @Howard-Wolowitz
yes
\[a _{n}=2a _{n-1}+3\] a some number lets substitute with 2 to find the value of the second variable \[a _{2}=2a _{2-1}+3\]
is this right @mathmate
Yes, continue! Use a table to help you. \(n~~~~a_{n-1}~~~~ a_n\) 1 - 0
ok
I gotta go use the restroom brb
keep going though
\[a _{2}=2a _{1}+3\] You subtract the 2-1
ok making 1
@mathmate Alright this is the step I'm a little confused on What do i do with the \[2a _{1}\]
If you use a table, life is soooo much easier. n \(a_{n-1}\) \(a_{n}\) 1 - 1 (given by question) 2 1 3 (a1 = 0 from previous line, so a2=2*0+3=3) ... continue this way
Sorry a1=0 n an−1 an 1 - 0 (given by question) 2 0 3 (a1 = 0 from previous line, so a2=2*0+3=3) ... continue this way
ok
ahhhhh omg that does make life easier xD
1 ____ 3 2 0 3 3 2 5 4 3 6 5 4 1
I see none that fit ;( @mathmate
1 ____ 3 2 0 3 3 3 ? You have to COPY an-1 from the previous line.
1 ____ 0 2 0 3 3 3 ? You have to COPY an-1 from the previous line.
ahhhhhhh so just keep it ok duh 3 3 3 4 3 ? correct ? I'm sorry I'm just new to a lot of these techniques :P @mathmate
1 - 0 (second number has nothing, a0 is not defined, a1 is given) 2 0 3 (second number is 0 from first line, 3 = 2*0+3) 3 3 ? (second number is 3 from 2nd line, ? =2*3+3) ....
ok :) 1 - 0 2 0 3 3 3 3 4 3 6 5 6 9 correct please tell me I'm right
|dw:1424786003870:dw| Your second column has to be derived from the third column of the previous line, \(a_{3-1}\) = a2
If you prefer, you can make only two columns: n an 1 0 2 3 3 ?
gtg
duh this is not speaking the numerical value of 1 its speaking -1 term not -1 numerically sorry
|dw:1424786236154:dw|
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