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Mathematics 7 Online
OpenStudy (howard-wolowitz):

Will fan and medal to the correct answer!

OpenStudy (howard-wolowitz):

Find the \[a ^{2}...a ^{3}...a ^{4}...\]

OpenStudy (howard-wolowitz):

OpenStudy (howard-wolowitz):

MATHMATEEEE HIIIII

OpenStudy (sparklestaraa):

www.Mathway.com

OpenStudy (howard-wolowitz):

how could that website work out this problem

OpenStudy (sparklestaraa):

it will find it for you if you type in this sequence/equation ;) Hope this helps. Also Wolfram Alpha but thats more complex to use

OpenStudy (sparklestaraa):

let me try it there for u :)

OpenStudy (howard-wolowitz):

it doesnt work when you get to the 3,

OpenStudy (sparklestaraa):

ya i just found that out ok wait again :P

OpenStudy (howard-wolowitz):

the answers are A. = 5,7,9 B. = 7,9,11

OpenStudy (howard-wolowitz):

C. = 5,8,11

OpenStudy (howard-wolowitz):

D. = 3,9,21

OpenStudy (howard-wolowitz):

tha being in the form of a2 a3 a4

OpenStudy (sparklestaraa):

ohhh ok then wait :P

OpenStudy (howard-wolowitz):

see it doenst work for crap like this

OpenStudy (sparklestaraa):

Alright let me see, step by step with each of these answers ok so A. = 5,7,9 B. = 7,9,11 C. = 5,8,11 D. = 3,9,21 remember A1=0 so if you are going by a1, a2,a3,a4 then its 0,5,7,9 0,7,9,11 0,5,8,11 0,3,9,21 ryt? do you understand so far @Howard-Wolowitz

OpenStudy (howard-wolowitz):

yes

OpenStudy (sparklestaraa):

\[a _{n}=2a _{n-1}+3\] a some number lets substitute with 2 to find the value of the second variable \[a _{2}=2a _{2-1}+3\]

OpenStudy (sparklestaraa):

is this right @mathmate

OpenStudy (mathmate):

Yes, continue! Use a table to help you. \(n~~~~a_{n-1}~~~~ a_n\) 1 - 0

OpenStudy (howard-wolowitz):

ok

OpenStudy (howard-wolowitz):

I gotta go use the restroom brb

OpenStudy (howard-wolowitz):

keep going though

OpenStudy (sparklestaraa):

\[a _{2}=2a _{1}+3\] You subtract the 2-1

OpenStudy (howard-wolowitz):

ok making 1

OpenStudy (sparklestaraa):

@mathmate Alright this is the step I'm a little confused on What do i do with the \[2a _{1}\]

OpenStudy (mathmate):

If you use a table, life is soooo much easier. n \(a_{n-1}\) \(a_{n}\) 1 - 1 (given by question) 2 1 3 (a1 = 0 from previous line, so a2=2*0+3=3) ... continue this way

OpenStudy (mathmate):

Sorry a1=0 n an−1 an 1 - 0 (given by question) 2 0 3 (a1 = 0 from previous line, so a2=2*0+3=3) ... continue this way

OpenStudy (howard-wolowitz):

ok

OpenStudy (sparklestaraa):

ahhhhh omg that does make life easier xD

OpenStudy (sparklestaraa):

1 ____ 3 2 0 3 3 2 5 4 3 6 5 4 1

OpenStudy (sparklestaraa):

I see none that fit ;( @mathmate

OpenStudy (mathmate):

1 ____ 3 2 0 3 3 3 ? You have to COPY an-1 from the previous line.

OpenStudy (mathmate):

1 ____ 0 2 0 3 3 3 ? You have to COPY an-1 from the previous line.

OpenStudy (sparklestaraa):

ahhhhhhh so just keep it ok duh 3 3 3 4 3 ? correct ? I'm sorry I'm just new to a lot of these techniques :P @mathmate

OpenStudy (mathmate):

1 - 0 (second number has nothing, a0 is not defined, a1 is given) 2 0 3 (second number is 0 from first line, 3 = 2*0+3) 3 3 ? (second number is 3 from 2nd line, ? =2*3+3) ....

OpenStudy (sparklestaraa):

ok :) 1 - 0 2 0 3 3 3 3 4 3 6 5 6 9 correct please tell me I'm right

OpenStudy (mathmate):

|dw:1424786003870:dw| Your second column has to be derived from the third column of the previous line, \(a_{3-1}\) = a2

OpenStudy (mathmate):

If you prefer, you can make only two columns: n an 1 0 2 3 3 ?

OpenStudy (mathmate):

gtg

OpenStudy (sparklestaraa):

duh this is not speaking the numerical value of 1 its speaking -1 term not -1 numerically sorry

OpenStudy (sparklestaraa):

|dw:1424786236154:dw|

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