A motorboat takes 5 hours to travel 200 km going upstream. The return trip takes 4 hours going downstream. What is the rate of the boat in still water and what is the rate of the current?
we can use the equation: distance = rate * time
Let me try. 200 = r x 5 5/200 = 40 r=40 (Slower) then 40-1 = 39 (Faster )
40+1 = 41
Still water rate?
Let r = rate of boat in still water c = rate of river current For upstream we have : 200 = ( r - c) * 5 Downstream we have : 200 = ( r + c) * 4
200 = (40-c)*5 (Up stream) 200= (40 + c)*5 (Downstream)
r is unknown
I thought R -= 40 from my 1st reply
R= 40 Let me try. 200 = r x 5 5/200 = 40 r=40 (Slower)
see there are actually two unknowns here the rate of the boat in still water, and the rate of the river stream. your equation does not reflect this .
I am so lost..
go over the equation in my last post above.
ok .. Let r = rate of boat in still water c = rate of river current For upstream we have : 200 = ( r - c) * 5 Downstream we have : 200 = ( r + c) * 4 How can I do any more if both r and c are unknown
we have two equations upstream 200 = ( r - c) * 5 downstream : 200 = ( r + c) * 4
we can solve a system of two equations in two unknowns
Up = 40 Down = 50
Not sure I see how that answers rates?
http://www.wolframalpha.com/input/?i=solve+200+%3D+%28+r+-+c%29+*+5+%2C+200+%3D+%28+r+%2B+c%29+*+4
They have a step by step solution there. :)
Let r = rate of boat in still water c = rate of river current For upstream we have : 200 = (45 - 5) * 5 Downstream we have : 200 = ( 45 + 5) * 4
Thank you!!!
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