F(x) = x 2 + 3x - 2 F(a) =
\(\large\color{black}{ \displaystyle F(x) = x^2 + 3x - 2 }\) to find \(\large\color{black}{ \displaystyle F(a) }\) plug in a instead of x.
I mean "a" is still a variable, so that doesn't make it any different.
can you plug in "a" for "x" ?
or want an example?
f(a)=x^2+3x-2?
no
you aren't just replacing the "x" with an "a" in `F(a)`. RATHER, you replace "x" with an "x" EVERYWHERE.
for example, if I wanted to find F(2) \(\large\color{black}{ \displaystyle F(2) = (2)^2 + 3(2) - 2 }\) then I will need to simplify (if that is a possibility) \(\large\color{black}{ \displaystyle F(2) = 4 +6 - 2 }\) \(\large\color{black}{ \displaystyle F(2) = 8 }\)
I think I get it. At least a little better.
yes, so how (do you think) you will find F(a)
(again, plug in "a" instead of "x" everywhere)
Order of operations?
no, just substitute "a" for "x"
\(\large\color{black}{ \displaystyle F(x) = x^2 + 3x - 2 }\) \(\large\color{black}{ \displaystyle F(a) =~~.... }\) (what will it equal ?)
f(a)=a^2=3a-2?
yes, if that second = sign was supposed to be a +
Thank you =)
you welcome !
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