Question

Find y' of x^2*(x-y)^2=x^2-y^2

Answer 1

Did you take the derivative of it yet?

Answer 2

Yeah but I think I screwed up the left side somehow hahah

Answer 3

Hmm, put what you got and we'll see what we can do about it :P

Answer 4

I have 2x(x-y)^2*x^2*2(x-y)(1-y) = 2x-2y*y

Answer 5

Wait need to put y'

Answer 6

2x(x-y)^2*x^2*2(x-y)(1-y')=2x-2y*y' ?

Answer 7

yes, now you need to isolate the y'

Answer 8

wait, there should be a plus in the middle on the left hand side

Answer 9

why don't we simplify it to get the simpler equation?

Answer 10

FOILing that looks like a lot of work xD

Answer 11

x^2*(x-y)^2=x^2-y^2

`2x(x-y)^2` + `x^2 2(x-y)(1-y')` = 2x-2y*y'

Answer 12

Yes you're right I put a * instead of a + I screwed that up

Answer 13

expanding? maybe... I don't find a need in doing that. But that is just me

Answer 14

\(x^2(x-y)^2=x^2-y^2\\x^2(x-y)(x-y) =(x-y)(x+y)\\x^2(x-y) =x+y\)

Answer 15

then expand and isolate y, take derivative then. you will be ok

Answer 16

yes, that is definitely an option:)
agree...

Answer 17

not that it is super hard to take the product rule at the beginning

Answer 18

Awesome thanks for the help guys!

Answer 19

yup.... I am sure you can isolate the y' (isolation should be something automatic, once you are in calc)
even I can do it:)