how do i solve this?

Question

anonymous · Answer

give me a sec to write it out

anonymous · Answer

$$\sqrt{\sqrt[3]{5}}$$

anonymous · Answer

i forgot how to

luigi0210 · Answer

Have you tried rewriting it?

anonymous · Answer

see that is what i am trying to figure out. how do i re-write it?

luigi0210 · Answer

$\Large \sqrt{\sqrt[3]{5}} =((5)^{1/3})^{1/2} $

luigi0210 · Answer

Now the property of exponents comes into play

anonymous · Answer

how does that go to $ ((5)^{1/3})^{1/2} $

anonymous · Answer

ik that $\sqrt[3]{5}$ is equal to $5^{\frac{1}{3}}$ right

luigi0210 · Answer

$\Large C^x*C^y=C^{x+y} $

$\Large (C^x)^y=C^{x*y} $



And because $\Large \sqrt{x} =x^{1/2} $
Where $\Large \sqrt[3]{x} =x^{1/3} $

misty1212 · Answer

HI!!

anonymous · Answer

ok so i know that  $\sqrt[3]{5}$ is equal to $5^{\frac{1}{3}}$ so we have $\sqrt{5^{\frac{1}{3}}}$ now?

misty1212 · Answer

you can also to it by multplying the indices without resorting to exponential notation

misty1212 · Answer

$$\huge \sqrt[n]{\sqrt[m]{x}}=\sqrt[mn]{x}$$

luigi0210 · Answer

If you're comfortable with exponents you can do what Misty said.

anonymous · Answer

oh i see then $\sqrt[mn]{x}$ equals $x^{\frac{1}{nm}}$

anonymous · Answer

sorry for the small text

luigi0210 · Answer

It's alright :P

You can use "\Large" or "\Huge" and so to make them bigger if you want :P

But yea, you know what's going on so far?

anonymous · Answer

yeah

anonymous · Answer

ok i was wondering because i was getting 1/3 for the exponent not 1/6 but i see what i did wrong

anonymous · Answer

can you guys help with another one?