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a) oxidation state of N in NH4N02 b) draw a lewis structure so both n's have a formal charge of +1
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Find the charges of the other elements in the compound. You'll notice that o2 is -4 and h4 must be -4 as well. that's a charge of -8 for nitrogen to neutralize this, each nitrogen must have a oxidation state of +4
Isn't H +4?
|dw:1424837074356:dw|One of the N has a charge of 1+ but the other doesn't.. I know N follows octet rule, so N attached to 5 things is not likely but when you break this compound up into its ions and do the individual lewis structres, n is attached to 4 H..
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