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Find derivative of cos 2x using chain rule? Please help, studying for midterm?
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do u understand d chain rule?
I understand the chain rule. Would you get (-sin x) (2x) (2)?
yep
wait its -sin2x
Okay the problem I'm having is with simplification.. what do I do from here?>
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just put d 2 in front of sin2x
I thought chain rule was f' x g x g'
so its -2sin2x
(-sin x) (2x) (2) simplifies to -2sin2x?
\[\frac{d}{dx} \left( \cos(2x) \right) = -\sin(2x) \times \frac{d}{dx} \left(2x \right)\]
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yes.
yep
(-sin x) (2x).. why wouldn't this be sin (2x^2)?
cause (-sin2x)(2) u cannot separate the 2x from sin they are married for life
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