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Chemistry 14 Online
OpenStudy (sleepyjess):

How many grams of zinc metal will react completely with 8.2 liters of 3.5 M HCl? Zn (s) + 2 HCl (aq) ---> ZnCl2 (aq) + H2 (g)

OpenStudy (sleepyjess):

@Abhisar

OpenStudy (abhisar):

Hello gurlie (-:

OpenStudy (sleepyjess):

hellow can you help meh?

OpenStudy (abhisar):

So, first let's calculate moles of HCl present in that solution. Moles = Molarity X Volume.

OpenStudy (abhisar):

Moles of HCl = ?

OpenStudy (sleepyjess):

12/1*8.2?

OpenStudy (sleepyjess):

99.22

OpenStudy (abhisar):

Nopes, Moles = 8.2 X 3.5 = 28.7

OpenStudy (abhisar):

Second step: 1 mole of HCl reacts with 0.5 mole of Zn. So 28.7 moles of HCl will react with 28.7 X 0.5 = ? moles of Zn.

OpenStudy (sleepyjess):

14.35

OpenStudy (abhisar):

Step 3: Convert the calculated moles of Zinc into grams by using its molar mass.

OpenStudy (sleepyjess):

93.7

OpenStudy (abhisar):

14.35 X 65.37

OpenStudy (sleepyjess):

ah whoops, typo 938.7

OpenStudy (abhisar):

|Correct,got it?

OpenStudy (sleepyjess):

wait, is that it?

OpenStudy (abhisar):

Yes..

OpenStudy (sleepyjess):

oh :)

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