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How many grams of zinc metal will react completely with 8.2 liters of 3.5 M HCl? Zn (s) + 2 HCl (aq) ---> ZnCl2 (aq) + H2 (g)
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@Abhisar
Hello gurlie (-:
hellow can you help meh?
So, first let's calculate moles of HCl present in that solution. Moles = Molarity X Volume.
Moles of HCl = ?
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12/1*8.2?
99.22
Nopes, Moles = 8.2 X 3.5 = 28.7
Second step: 1 mole of HCl reacts with 0.5 mole of Zn. So 28.7 moles of HCl will react with 28.7 X 0.5 = ? moles of Zn.
14.35
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Step 3: Convert the calculated moles of Zinc into grams by using its molar mass.
93.7
14.35 X 65.37
ah whoops, typo 938.7
|Correct,got it?
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wait, is that it?
Yes..
oh :)
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