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There are 8 men and 4 women in a group. If 3 men and 2 women are chosen to be arranged in a line, how many distinct line-ups are there?
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The answer to this was 40320. Which is not equivalent to what you were saying. That was what I also thought, but then it was wrong
Are there any missing infos?
None
The number of combinations of 3 men and 2 women is given by 8C3 * 4C2 = 336 Each of these 336 combinations of 3 men and 2 women can be arranged in 5! ways. Therefore the number of distinct line-ups is given by: \[\large 336\times5\times4\times3\times2\times1=you\ can\ calculate\]
Woah. Thanks for that
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AH, never thought of the 5 ways
You're welcome :)
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