I JUST CAN'T get the hang of these. In tears! Two cyclists leave towns 76 mi apart at the same time and travel toward each other. One cyclist travels 6 mph faster than the other. If they meet in 2 hours, what is the rate of each cyclist?
what is rate of speed of cyclist 1?
umm... I need to figure the rate of both bikes
well the answer is i do not know so we would let that be x cyclist 2 would x+6 you know the time 2 and the distance 76 2x+2(X+6) = 76 solve this for x
You could also think about it like this: since there are 2 cyclists and 1 is traveling FASTER than the other, then let: cyclist 1 = x (the one that's moving slower) cyclist 2 = x+6 (this guy is travelling 6 miles FASTER than the first guy)
2x + 2(x+6) = 76 2x + 12 = 76
2x + 2(x+6) = 76 2x +2x+ 12 = 76
2x + 2(x+6) = 76 2x + 12 = 76 12/76 = 6.333
As d = rt (distance = rate TIMES time) , and we know the rate of cyclist 1 and 2, then : d\(_1\) = 70 mi = 2x d\(_2\) = 2(x+6)
Combining these two, since they are both travelling the same distance, we get \[70 = 2x +2(x+6)\]
2x + 2(x+6) = 76 4x + 24 = 76
First of all, is what me and @zpupster making sense?
4x + 12 = 76
It's easy to plug and chug, but are you understanding the concept?
I think it is a rate x distance = time?
No. distance = rate x time
That is why you are multiplying `2` to both rates,
2(x) and 2(x+6)
6 x 2 = Distance
Does 6 \(\times\) 2 = 70?
No 12
this was right just solve for x 4x + 12 = 76
x = 76 - 12
No.
4x = 76 - 12*
4x = 76 - 12
x = 76 + 12 x = 88
4/88=11
That is wrogn.
x = 11 11+ 6 = 17 faster
You don't really seem like you know what you are doing.
I have been trying for a week. My teacher is ignoring me
First of all, where did your 4 disappear to? 4x = 76 - 12 suddenly became x = 76 - 12
slow down faine take a breath then let start with 4x = 76 - 12
That is why I am crying. I have been sitting here all day doing one after another and all were wrong
I divided my 4 into the 88 to get 11
I think what you are confused with starting from the top is understanding what the RATE of each cyclist is, and why one is labeled as x and the other is labeled as x+6.
x = 64 @zpupster
Once you understand that, you can associate that with the distance formula, d = rt, where the time for BOTH is 2 hours.
4x=64
yes
4/64 = 16
That's correct.
divide both sides by 4
Now you've got the rate of the slower cyclist.
16 + 6 = 22
All you need to do is figure out how much faster the other one is moving, which you just got as well.
good job!!!
Now retry this problem without looking.
Answer me this, what if the problem said `one cyclist is moving SLOWER than the other`?
w would you write the rate of cyclist #2?
How do I medal all of you? I can not believe my stupidity is this obvious and I am feeling dumb. I'm in friggin college for sanity sake! How did I get this far. THANK YOU ALL!!!!!!!
16 - 6 = 10 If it were 6 mph slower?
Awesome.
I hope these stay in my abccount so I can look back on what we did and try a few alone
And if the problem said they were moving against eachother, then you would subtract the rates.
Join our real-time social learning platform and learn together with your friends!