Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (horsegirl27):

I need someone to help me through my homework!

OpenStudy (horsegirl27):

OpenStudy (horsegirl27):

Please help I will medal.

OpenStudy (horsegirl27):

@iGreen @koolkat13

OpenStudy (horsegirl27):

Ok thanks for looking at it

OpenStudy (igreen):

First we have to find the starting prices and growths for functions A, B, and C.

OpenStudy (horsegirl27):

ok. How do I do that?

OpenStudy (igreen):

Function A already tells you.. \(\sf f(x) = \color{red}{25}(1.\color{blue}{08})^x\) \(\sf \color{red}{Starting~Price}\) \(\sf \color{blue}{Rate-of-Growth}\)

OpenStudy (horsegirl27):

Function B the starting price is 22, Function C starting price 30?

OpenStudy (horsegirl27):

Function B goes up by 1.56 and C by .04?

OpenStudy (igreen):

Correct!

OpenStudy (horsegirl27):

Yay!

OpenStudy (igreen):

\(\color{blue}{\text{Originally Posted by}}\) @horsegirl27 Function B the starting price is 22, Function C starting price 30? \(\color{blue}{\text{End of Quote}}\) Well for this

OpenStudy (horsegirl27):

ok

OpenStudy (igreen):

\(\color{blue}{\text{Originally Posted by}}\) @horsegirl27 Function B goes up by 1.56 and C by .04? \(\color{blue}{\text{End of Quote}}\) You're right about C, it increases by 4%, but not about B.

OpenStudy (horsegirl27):

Ok. What is the rate of growth for B? I wasn't too sure the way it's written...

OpenStudy (horsegirl27):

I remember in the lesson something about adding 1 and it's seen it function A... when do I do that step?

OpenStudy (igreen):

Hold on

OpenStudy (horsegirl27):

ok

OpenStudy (igreen):

Okay, function B decreases by 2%.

OpenStudy (igreen):

So we have: Function A: Starting Price = 25 Growth = 8% Function B: Starting Price = 22 Growth = 2% Function C: Starting Price = 30 Growth = 4%

OpenStudy (horsegirl27):

Ok how did you get the rate of growth for B?

OpenStudy (horsegirl27):

Oh so for stock D I'm using this information to make a function right? It says use the second lowest starting price and second highest rate of growth

OpenStudy (horsegirl27):

So it would be f(x)=25(1.04)^x for function D right?

OpenStudy (igreen):

2nd lowest.. We have: 30, 25, 22 So it has to be between 25 and 22.

OpenStudy (horsegirl27):

Oh I see

OpenStudy (horsegirl27):

Are you sure?

OpenStudy (igreen):

Yes..2nd lowest..so it has to be between the lowest, and the next lowest.

OpenStudy (igreen):

Pick any number between 25 and 22

OpenStudy (horsegirl27):

23

OpenStudy (horsegirl27):

And I pick a number between 4% and 8% for second highest?

OpenStudy (igreen):

Yep

OpenStudy (igreen):

Which do you want to pick?

OpenStudy (horsegirl27):

6%

OpenStudy (igreen):

Okay, let's do a 6% increase, so we have: \(f(x) = 23(1.06)^x\)

OpenStudy (horsegirl27):

ok

OpenStudy (igreen):

Here's the graph: https://www.desmos.com/calculator/6ujurwld5v

OpenStudy (horsegirl27):

Thanks!

OpenStudy (horsegirl27):

So @iGreen I don't understand how to do C. I understand what is happening, but I'm not sure how to do it

OpenStudy (igreen):

It affects Stock D by -6. \(f(x) = 23(1.06)^x\) \(g(x) = -6\) Find \(f(x) + g(x)\): \(23(1.06)^x + -6\) \(23(1.06)^x - 6\)

OpenStudy (horsegirl27):

oh ok

OpenStudy (igreen):

It just makes f(x) shift down 6 units

OpenStudy (igreen):

Here's a graph of it: https://www.desmos.com/calculator/zcf25epwsa

OpenStudy (horsegirl27):

that makes sense thanks

OpenStudy (horsegirl27):

now for 4 what are the effects? Can you help me explain?

OpenStudy (igreen):

Here: https://www.desmos.com/calculator/h4wjbmbz1p

OpenStudy (igreen):

The first one makes the exponent greater, so it rises more quickly. The 2nd one makes the exponent negative, so it makes the graph decrease. The third one just shifts the graph up 3 times.

OpenStudy (horsegirl27):

ok. so each changes the graph. Thanks for helping me! Later I might need help with another, I will tag you

OpenStudy (igreen):

No problem.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!