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Mathematics 15 Online
OpenStudy (17jeisaac):

Which logarithmic function has x = 5 as its vertical asymptote and (6, 0) as the x-intercept? (x is the variable.) The logarithmic function is f(x) = log ?

OpenStudy (solomonzelman):

Lets start from this. What is the vertical asymptote and x-intercept of a parent (initial) function \(\large\color{black}{ f(x)={\rm Log}(x) }\) ?

OpenStudy (17jeisaac):

@SolomonZelman I don't know.

OpenStudy (solomonzelman):

alright.... so lets explore it then.... are you aware of 1. \(\large\color{black}{ {\rm Log}(a^b) ~~~\Rightarrow ~~~b~{\rm Log}(a) }\) 2. `1 / A = A^(-1) ` ??

OpenStudy (17jeisaac):

@SolomonZelman No.

OpenStudy (solomonzelman):

oh, ok, but do you understand the rules from now since I posted them?

OpenStudy (17jeisaac):

@SolomonZelman No I don't understand any of this.

OpenStudy (solomonzelman):

you don't give me any proper background to work with.

OpenStudy (solomonzelman):

when you understand these rules, I will try to help, but honestly ... I am sorry.

OpenStudy (17jeisaac):

@SolomonZelman I know the vertical asymptote is x=0 and the x intercept is one.

OpenStudy (solomonzelman):

alright.... I guess we won't deal with why this is so, but lets just (rather) take it as given \(\large\color{black}{ y={\rm Log}(x) }\) x-intercept is (1,0) and vertical asymptote is x=0

OpenStudy (solomonzelman):

now, you want the function to have the vertical asymptote of x=5, so shift the function 5 units right

OpenStudy (17jeisaac):

@SolomonZelman so that's plus 5?

OpenStudy (solomonzelman):

yes, where do you put the +5 ?

OpenStudy (17jeisaac):

@SolomonZelman I have no clue

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