Mathematics
8 Online
OpenStudy (jennyrlz):
Write the sum using summation notation, assuming the suggested pattern continues.
-10 - 2 + 6 + 14 + ... + 110
11 years ago
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OpenStudy (michele_laino):
your sequence is an arithmetic sequence with constant d= 8
11 years ago
OpenStudy (michele_laino):
first term is:
\[{a_1} = - 10\]
11 years ago
OpenStudy (jennyrlz):
ok i understand that
11 years ago
OpenStudy (michele_laino):
n-th term is:
\[{a_n} = 110\]
11 years ago
OpenStudy (michele_laino):
what is n?
11 years ago
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OpenStudy (michele_laino):
or, in other words how many terms have you got in your sequence?
11 years ago
OpenStudy (jennyrlz):
5 terms?
11 years ago
OpenStudy (jennyrlz):
so n is equal to 5
11 years ago
OpenStudy (michele_laino):
I don't think, you have to apply this formula:
\[{a_n} = {a_1} + (n - 1) \cdot d\]
where d= 8, a_1 = -10, and a_n = 110, so please solve that equation for n
11 years ago
OpenStudy (jennyrlz):
ok one sec
11 years ago
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OpenStudy (michele_laino):
hint:
\[n - 1 = \frac{{{a_n} - {a_1}}}{d} = \frac{{110 - \left( { - 10} \right)}}{8} = ...?\]
11 years ago
OpenStudy (jennyrlz):
15 :D
11 years ago
OpenStudy (michele_laino):
please wait you got:
n-1 = 15 so what is n?
11 years ago
OpenStudy (jennyrlz):
14
11 years ago
OpenStudy (solomonzelman):
just find the pattern, and put it in the \(\large\color{blueviolet}{ \displaystyle \sum_{ }^{ } ~}\)
11 years ago
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OpenStudy (solomonzelman):
yes, find whichTH term 110 is, and do the sigma
11 years ago
OpenStudy (michele_laino):
hint:
if n-1 = 15, then
n = 15+1=...?
11 years ago
OpenStudy (solomonzelman):
if anyone needs the latex for inline sigma, then
```
\(\large\color{blueviolet}{ \displaystyle \sum_{ n=1 }^{ \infty } ~ f(n)}\)
```
11 years ago
OpenStudy (jennyrlz):
N=16
11 years ago
OpenStudy (michele_laino):
that's right! so in you sequence there are 16 terms
11 years ago
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OpenStudy (jennyrlz):
Ok!
11 years ago
OpenStudy (michele_laino):
now, in order to get the sum S of tose terms, you have to apply this formula:
\[S = \frac{{{a_1} + {a_n}}}{2}n\]
11 years ago
OpenStudy (michele_laino):
oops.. those terms...
11 years ago
OpenStudy (michele_laino):
hint:
\[S = \frac{{{a_1} + {a_n}}}{2}n = \frac{{ - 10 + 110}}{2} \cdot 16 = ...?\]
11 years ago
OpenStudy (jennyrlz):
800...?
11 years ago
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OpenStudy (michele_laino):
well done! Congratulations! :)
11 years ago
OpenStudy (jennyrlz):
:D
11 years ago
OpenStudy (jennyrlz):
Is that it...?
11 years ago
OpenStudy (michele_laino):
yes! it is!
11 years ago
OpenStudy (jennyrlz):
But it doesn't match any of the answers given 0.0
11 years ago
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OpenStudy (jennyrlz):
The answers have the "E"
11 years ago
OpenStudy (jennyrlz):
I can't make it on this key board :/
11 years ago
OpenStudy (michele_laino):
please wait I think that @SolomonZelman is right! since we have to write in the sum notation
11 years ago
OpenStudy (jennyrlz):
Ok :)
11 years ago
OpenStudy (michele_laino):
so our result, since there are infinite terms is:
\[\sum\limits_1^\infty {{a_1} + \left( {n - 1} \right)} \,d\]
11 years ago
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OpenStudy (jennyrlz):
S there are no longer 16 terms...?
11 years ago
OpenStudy (michele_laino):
please you have to substitute a_1 and d with our numerical values
11 years ago
OpenStudy (jennyrlz):
A1=-10 d=8
11 years ago
OpenStudy (michele_laino):
no I don't think, since your problem says "assuming that the pattern"
11 years ago
OpenStudy (michele_laino):
ok! sbstitute a_1 = -10 andd = 8, into this formula
\[\sum\limits_1^\infty {{a_1} + \left( {n - 1} \right)} \,d\]
11 years ago
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OpenStudy (jennyrlz):
Ahh ok
11 years ago
OpenStudy (jennyrlz):
So what do I put for n?
11 years ago
OpenStudy (jennyrlz):
E(-10)+(8n-8)
11 years ago
OpenStudy (michele_laino):
please unchanged n, write n without any substitution for it
11 years ago
OpenStudy (michele_laino):
yes! now simplify like terms, namely what is:
-10+8n-8=...?
11 years ago
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OpenStudy (jennyrlz):
?
11 years ago
OpenStudy (jennyrlz):
So (n-8)?
11 years ago
OpenStudy (michele_laino):
you should get this:
\[\sum\limits_1^\infty {8n - 18} \]
11 years ago
OpenStudy (jennyrlz):
-18
11 years ago
OpenStudy (michele_laino):
since -10 + 8n - 8= 8n-18
11 years ago
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OpenStudy (michele_laino):
no, 8n-18
11 years ago
OpenStudy (jennyrlz):
I am on an I pad so sorry if everything is taking forever to load if for you
11 years ago
OpenStudy (michele_laino):
please we have:
(-10)+(8n-8)= 8n-18
11 years ago
OpenStudy (michele_laino):
+ 8n
11 years ago
OpenStudy (michele_laino):
-18 + 8n
11 years ago
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OpenStudy (michele_laino):
(-10)+(8n-8) = -10 + 8n -8 = -10 - 8 +8n = -18 + 8n
11 years ago
OpenStudy (jennyrlz):
That still doesn't match any of my answers T.T
11 years ago
OpenStudy (michele_laino):
it is a simplification, since I have combined similar terms
11 years ago
OpenStudy (jennyrlz):
E=-80n
E=(-10+8n)
11 years ago
OpenStudy (jennyrlz):
Tose are the answer choices
11 years ago
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OpenStudy (michele_laino):
and the result is:
\[\sum\limits_1^\infty {8n - 18} \]
11 years ago
OpenStudy (jennyrlz):
those done match any of my answer options
11 years ago
OpenStudy (michele_laino):
please is it clear?
11 years ago
OpenStudy (jennyrlz):
E=-80n
or E=(-10+8n)
11 years ago
OpenStudy (michele_laino):
if not I will give you more explanation
11 years ago
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OpenStudy (jennyrlz):
are you still there? ;-;
11 years ago
OpenStudy (jennyrlz):
wait you lost me ; ;
11 years ago
OpenStudy (jennyrlz):
the answer we got doesnt match any of the answer choices
11 years ago
OpenStudy (michele_laino):
ok! I'm here!
11 years ago
OpenStudy (michele_laino):
please what are your choices?
11 years ago
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OpenStudy (jennyrlz):
ok the answer choices are either E=-80n or E= (-10+8n)
11 years ago
OpenStudy (michele_laino):
then it is the second option
11 years ago
OpenStudy (jennyrlz):
ok and there are two of the "second" option
on has a 15 over the E and the other has an infinity symbol over it
11 years ago
OpenStudy (michele_laino):
please wait, are you reading them from your textbook?
11 years ago
OpenStudy (jennyrlz):
no
11 years ago
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OpenStudy (jennyrlz):
this is from an assignment the teacher gave us
11 years ago
OpenStudy (michele_laino):
then you have to pick the one which has an infinity symbol
11 years ago
OpenStudy (jennyrlz):
ok thanks :DDD
11 years ago
OpenStudy (michele_laino):
thanks! :)
11 years ago