A 1,700 kg car coasts down a hill starting from rest and decreases its height by 22 m over a distance of 110 m of travel. How fast will it be going at the end of the hill, if friction has no effect in slowing its motion?

Question

anonymous · Answer

The gain in kinetic energy, (1/2)m v^2 
= the loss in potential energy, m g h.
Solve for v. 
Height crucial, distance irrelevant

justin_lee · Answer

You wrote out everything you need already. Plus remove mass from either side and solve for v.

justin_lee · Answer

Just plug in the values for g and h. h = 22 m. g = 9.81 m/s^2.