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Chemistry 19 Online
OpenStudy (sleepyjess):

@Abhisar

OpenStudy (abhisar):

Can we have the question again?

OpenStudy (sleepyjess):

yes

OpenStudy (sleepyjess):

How many grams of a stock solution that is 87.5 percent H2SO4 by mass would be needed to make 275 grams of a 55.0 percent by mass solution? Show all of the work needed to solve this problem.

OpenStudy (abhisar):

So, \(\huge \boxed{\tt Mass \text{%} = \frac{Mass~of~the~solute}{Mass~of~solution}\times 100}\)

OpenStudy (abhisar):

In the 275 gram of 55% by mass solution, mass of solute (x) can be found as \(\tt \huge \frac{x}{275}\times 100 = 55\), solving it you will get x=151.25

OpenStudy (sleepyjess):

oohhh :)

OpenStudy (sleepyjess):

I am lagging really bad

OpenStudy (abhisar):

Yeah, I am lagging too. This is not done doe.

OpenStudy (abhisar):

@sleepyjess , Are you done with this?

OpenStudy (sleepyjess):

oh yeah :)

OpenStudy (abhisar):

Good ! \(\color{olive}{\Huge\widehat{\underset{^\backslash \textrm{____} ^/}{\left\{\underset{\color{#aa1111}{\leftrightsquigarrow}}{\!\!\!\color{red}{\bigodot}\,_{\Large\color{#0f500f}{\bullet\bullet}}\Huge\color{red}{\bigodot}\!\!\!}\right\}}}}\)

OpenStudy (sleepyjess):

hehe

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