Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (abhisar):
Can we have the question again?
OpenStudy (sleepyjess):
yes
OpenStudy (sleepyjess):
How many grams of a stock solution that is 87.5 percent H2SO4 by mass would be needed to make 275 grams of a 55.0 percent by mass solution? Show all of the work needed to solve this problem.
OpenStudy (abhisar):
So,
\(\huge \boxed{\tt Mass \text{%} = \frac{Mass~of~the~solute}{Mass~of~solution}\times 100}\)
OpenStudy (abhisar):
In the 275 gram of 55% by mass solution, mass of solute (x) can be found as
\(\tt \huge \frac{x}{275}\times 100 = 55\), solving it you will get x=151.25
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (sleepyjess):
oohhh :)
OpenStudy (sleepyjess):
I am lagging really bad
OpenStudy (abhisar):
Yeah, I am lagging too. This is not done doe.
OpenStudy (abhisar):
@sleepyjess , Are you done with this?
OpenStudy (sleepyjess):
oh yeah :)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (abhisar):
Good !
\(\color{olive}{\Huge\widehat{\underset{^\backslash \textrm{____} ^/}{\left\{\underset{\color{#aa1111}{\leftrightsquigarrow}}{\!\!\!\color{red}{\bigodot}\,_{\Large\color{#0f500f}{\bullet\bullet}}\Huge\color{red}{\bigodot}\!\!\!}\right\}}}}\)