@Abhisar
Can we have the question again?
yes
How many grams of a stock solution that is 87.5 percent H2SO4 by mass would be needed to make 275 grams of a 55.0 percent by mass solution? Show all of the work needed to solve this problem.
So, \(\huge \boxed{\tt Mass \text{%} = \frac{Mass~of~the~solute}{Mass~of~solution}\times 100}\)
In the 275 gram of 55% by mass solution, mass of solute (x) can be found as \(\tt \huge \frac{x}{275}\times 100 = 55\), solving it you will get x=151.25
oohhh :)
I am lagging really bad
Yeah, I am lagging too. This is not done doe.
@sleepyjess , Are you done with this?
oh yeah :)
Good ! \(\color{olive}{\Huge\widehat{\underset{^\backslash \textrm{____} ^/}{\left\{\underset{\color{#aa1111}{\leftrightsquigarrow}}{\!\!\!\color{red}{\bigodot}\,_{\Large\color{#0f500f}{\bullet\bullet}}\Huge\color{red}{\bigodot}\!\!\!}\right\}}}}\)
hehe
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