Question

The proportion of a population with a characteristic of interest is p = 0.37. Find the mean and standard
deviation of the sample proportion P^ obtained from random samples of size 125.

Answer 1

for large samples we have

Answer 2

so the mean is 0.37

Answer 3

yes

Answer 4

but what does q and n stand for ?

Answer 5

i think thats where im confused

Answer 6

\[ \text {For large samples, the sample proportion is approximately normally distributed, with mean}\\ \huge \mu_\hat{p}= p \\ \text{and standard deviation} \\ \huge \sigma_\hat{p}=\sqrt{\frac{pq}{n}}\]

Answer 7

q = 1 - p ,
and n is the size of your sample

Answer 8

q is the complement of p

Answer 9

so it would be sqrt(1-0.37)/125

Answer 10

\[\huge \sigma_\hat{p}=\sqrt{\frac{p(1-p)}{n}}\]

Answer 11

And the answer I got was 0.071?

Answer 12

Im not sure if that's right =0

Answer 13

\[\huge \sigma_\hat{p}=\sqrt{\frac{.37(.63)}{125}}\]

Answer 14

ohh you multiply the 0.37 and .63!

Answer 15

yes :)

Answer 16

so it would be .0432!

Answer 17

well nvm it would be 0.043!
thank you so much for breaking down the formula to me!!