When calculating allele frequencies in the Hardy-Weinberg equation, why can you not simply use the dominant phenotype to calculate p? A-You actually can calculate p from the dominant phenotype by dividing the number of dominant individuals in a population by the total number of individuals in a population. B- The dominant phenotype cannot be calculated because the total number of individuals in the population is unknown. C- The dominant phenotype is represented by pand q. D- The dominant phenotype represents both homozygous and heterozygous genotypes.
I say C need second opinion
@shrutipande9
see...i will give u an eg... Y is yellow seeds and y green seeds. Now YY and Yy give yellow seeds. But p in hardy weinberg only gives frequency of dominant allele. we also need 2pq to find out frequency of heterozygotes. because heterozygotes also give dominant phenotype
after reading yhat i still say C . Unless im wrong and i can do more research.
Now im looking at B
see...Y is dominant allele...and yellow seeds in dominant phenotype. we can get dominant allele when we have Y but if we want dominant phenotype then we can get it with YY or Yy. u get me?
So b
nope
I know its not D, and if its not B, then either A or C
I dont think its A
y do u think its not D or B?
Bcause the punnet square gives us the results so we know the numbers
its D @shrutipande9
In the equation, p represents the frequency of the dominant allele and q is the frequency of the recessive allele. An easy way to remember this is that in the alphabet, p comes before q, and in genetics, the dominant allele is written before the recessive allele.
cool..:D
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