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Write an equation that could be used to find the value of b. 38^2 = 2^2 + 3^2 – 2(2)(3)(cos b°) b^2 = 2^2 + 3^2 – 2(2)(3)(cos 38°) 2^2 = b^2 + 3^2 – 2(b)(3)(cos 38°) 3^2 = 2^2 + b^2 – 2(2)(b)(cos 38°)
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@butterflydreamer
@Michele_Laino
please if I apply the Carnot Theorem, I get: \[{b^2} = {c^2} + {a^2} - 2ac\cos \left( {38} \right)\]
with a=2 and c=3
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so would it be: b^2 = 2^2 + 3^2 – 2(2)(3)(cos 38°) ?
yes!
ok thanks so much :)
thanks! :)
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