Question

Can someone help me through my homework?

Answer 1

Give me a second to post it

Answer 2

@iGreen can you help again? I got a 100% on what you helped with :D

Answer 3

Please help me @iGreen

Answer 4

Anyone? I need some help

Answer 5

@jim_thompson5910 @ganeshie8 @sleepyjess @AnswerMyQuestions

Answer 6

@Nnesha Can you please help her?

Answer 7

can you rewrite
\[ \left( 2^6\right)^x \]
?

Answer 8

I'm not sure how @phi

Answer 9

They usually don't give complicated problems until after you have studied easy problems.
so you should have learned this rule:
\[ \left( a^b\right)^c = a^{bc} \]
in other words, you can multiply the exponents b*c
example:
\[ \left( 2^3\right)^4 = 2^{3 \cdot 4} = 2^{12}\]

can you use that rule to rewrite
\[ \left( 2^3\right)^x \]?

Answer 10

ok

Answer 11

2^3x

Answer 12

right?

Answer 13

yes. now for your problem
\[ \left(2^6 \right)^x= 2^{6x} \]

Answer 14

ok

Answer 15

now use the rule
\[ \sqrt[a]{b} = \left( b \right)^\frac{1}{a} \]
the little "a" next to the root sign is turned into the fraction 1/a and made an exponent
for our problem, b is "complicated" = \( 2^{6x} \)
but that does not matter. write:
\[ \sqrt[3]{2^{6x}} = \left(2^{6x} \right)^\frac{1}{3} \]

Answer 16

now use the first rule again: multiply the 6x times the 1/3
to get a new exponent.
can you do that ?

Answer 17

yes

Answer 18

2^3x?

Answer 19

the x part is ok. but what is 6 * 1/3 ?

Answer 20

oops 2!

Answer 21

yes, so
\[ 2^{2x} \]
now we use the first rule, but "backwards"
the exponent is 2 times x, so we can "undo" that and write it as
\[ \left(2^2\right)^x \]
does that make sense?

Answer 22

Sort of.

Answer 23

Actually it does

Answer 24

notice we could also write
\[ 2^{2x} = \left(2^x\right)^2 \]
but for this problem we want to write it as
\[ 2^{2x} = \left(2^2\right)^x \]
do you have any idea what 2^2 is ? (what number?)

Answer 25

4

Answer 26

yes, which means
\[ \left(2^2\right)^x = (4)^x = 4^x \]

Answer 27

ok

Answer 28

that would mean Anna is correct

Answer 29

so anna did it correctly
blake did something goofy
christine wrote the little "root 3" as exponent 3 instead of 1/3

Answer 30

ok

Answer 31

Now what about number 2 @phi

Answer 32

@iGreen help!

Answer 33

@Sweeni

Answer 34

@triciaal @satellite73 @iGreen @Nnesha help me!!!

Answer 35

@ribhu please help

Answer 36

which question?

Answer 37

2-4

Answer 38

Maybe you should do your own homework. Since everyone on here is giving out direct answers without explanations, so the asker won't learn anything. My advice is, you should do it yourself. I went through the messages on this post and you seem very smart, you have the answer for every question. You seem as though you know what you're doing, so why not give it a go? My advice is, you should do them by yourself, so you can at least learn something. These aren't difficult questions either, good luck.

Answer 39

Ok. I just doubt myself and like someone there to help me when I feel I need it. And I am learning. and I do need help getting started I'm not sure what to do as my first step

Answer 40

Um hi

Answer 41

@horsegirl27 u there i have solved 3 & 4 also but not able to post them

Answer 42

me

Answer 43

?

Answer 44

solutions to 2,3&4

Answer 45

@Supermariofan153 i hope solutions are legible

Answer 46

You have good handwriting I can read the first page I will look at the others

Answer 47

so for 4, basically he's correct that if the length is irrational, the area and perimeter are always irratioal?

Answer 48

*irrational

Answer 49

yeah

Answer 50

And 3 is a little hard to read... But could you briefly explain it? at least the key points then I will be able to figure out what you wrote

Answer 51

ok

Answer 52

http://www.twiddla.com/2012648

Answer 53

join this

Answer 54

Illuminati confirmed.

Answer 55

what??

Answer 56

ok

Answer 57

come to the whiteboard

Answer 58

Twiddling in progress...

Answer 59

yes even u r welcome @OpiGeode

Answer 60

Did you just call me the b word?

Answer 61

so u were there?

Answer 62

Yes I was just looking.

Answer 63

sorry!!

Answer 64

If you didn't want me to see it then you should have messaged her the link.

Answer 65

its fine! u can come and see and i am sorry for that.

Answer 66

Get horsegirl to come there. She isn't there yet.

Answer 67

no she is not, but i solved the questions correctly. u've blocked me!!

Answer 68

Yes I've blocked you because you weren't being that nice.

Answer 69

i am sorry, if u cud unblock me?

Answer 70

Did it

Answer 71

i can be of great help

Answer 72

You sure?

Answer 73

Ok I'm back

Answer 74

Hee hee.