Question

Can somebody help with radicals?

Answer 1

\[\sqrt{8}\times \sqrt{32}\]

Answer 2

Multiplying radicals isn't as tricky as it appears.
Just put them both in one radical, and multiply accordingly :D

Answer 3

TL ; DR ?
\[\Large a,b > 0\\\Large \sqrt a \cdot \sqrt b = \sqrt{ab}\]

Answer 4

What about
\[\sqrt{20b^3c^4}\] @Supreme_Kurt

Answer 5

Ahh. Now it gets more interesting :P
First, all the plain numbers (the non-letter ones)
You'll want to factor them out.

Factor them now.

Let me know when you're done. ^^

Answer 6

\[4\sqrt{5}\] right?

Answer 7

Well, no :)
4 comes out of the radical, but it becomes 2, since the square root of 4 is 2.

Answer 8

oh okay. soooo
\[2\sqrt{5}\]

Answer 9

Yup. But that's not all of it. You have to do something about the letters too :)

Answer 10

\[2bc^2\sqrt{5b}\]
maybeee?

Answer 11

That's correct. Your instincts serve you well :P

Answer 12

What about one like this?
\[^4\sqrt{80b^4c^3}\]

Answer 13

uh'oh.. tricky :D
Much like square roots, but this time, only ones with exponents that reach up to 4 can get out or the radical sign.

Answer 14

Okay so like it wouldbe?
\[2b ^4\sqrt{5c^3}\]

Answer 15

Well, b^4 makes an exit, but much like 4 exits and becomes 2, b^4 loses its exponent :)

Answer 16

Yeaah, yeah. I meant to put the 4 with the radical but it wouldn't move over D:

Answer 17

oh.

In that case, well done :)

Answer 18

Okay last one, I promise. How would I do this one?\[\left(\begin{matrix}^3\sqrt{4a} \\ ^3\sqrt{a^2}\end{matrix}\right)\]
It's suppose to be a fraction :-)

Answer 19

If you are having trouble with radicals you can express as fractions \[\sqrt[a]{x^n}=x^{\frac{n}{a}} \]\[\sqrt[5]{x^{10}}=x^{\frac{10}{5}}=x^2\]

Answer 20

Oh, okay. Thank y'all! @Supreme_Kurt & @Nishant_Garg