Question

Is there any such property??

Answer 1

\[\ln(a)=-\ln(-a)\]

Answer 2

i know about \[\ln(a)=-\ln(\frac{1}{a})\]

Answer 3

is "a" real ?

Answer 4

yes

Answer 5

also \[\ln(\frac{x}{2})+C\]
implies \[\ln(x)+C\]?
C is arbitrary constant

Answer 6

that looks fine..

ln(x/2) + C = ln(x) - ln(2) + C = ln(x) + D

where D = C - ln(2)

Answer 7

http://www.wolframalpha.com/input/?i=solve+ln%28x%29+%3D+-ln%28-x%29+over+reals

Answer 8

Thanks

Answer 9

np :) notice C is as much arbitrary as C+2 or C+3

i guess we can say, adding a number to an arbitrary constant wont change its arbitrariness ;)