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Mathematics 7 Online
OpenStudy (anonymous):

The graph shown is a direct variation. What is the rate of change?https://lcboe.owschools.com/media/o_coordalg_ccss_2014/1/5x.gif

OpenStudy (anonymous):

same as the slope do you know how to find it?

OpenStudy (igreen):

Take any points and plug them into here: \(m = \dfrac{y_2-y_1}{x_2-x_1}\)

OpenStudy (igreen):

any points on the line*

OpenStudy (anonymous):

k=y/x?

OpenStudy (anonymous):

actually not necessary in the case of direct variation is it?

OpenStudy (anonymous):

(5,25) (10,50)

OpenStudy (anonymous):

just pick a point i pick (10,50) slope is second number over the first \[\frac{50}{10}=5\]

OpenStudy (anonymous):

lol yal just taught me way more than what my teacher has lol

OpenStudy (anonymous):

also note that \[\frac{25}{5}=5\] too

OpenStudy (anonymous):

use the points (10,50) and (0,0)

OpenStudy (anonymous):

with direct variation you don't use two points it is the second number divided by the first

OpenStudy (anonymous):

glad to help, hope it is clear

OpenStudy (chosenmatt):

yes

OpenStudy (anonymous):

rate of change, \[\frac{dy}{dx}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{50-0}{10-0}=\frac{50}{10}=5\]

OpenStudy (anonymous):

Yes thank all of you im not gunna give a medal because all of you helped me understand and i am extremely grateful!!! THANK YOU!!!!!!!!!!!!

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