The graph shown is a direct variation. What is the rate of change?https://lcboe.owschools.com/media/o_coordalg_ccss_2014/1/5x.gif
same as the slope do you know how to find it?
Take any points and plug them into here: \(m = \dfrac{y_2-y_1}{x_2-x_1}\)
any points on the line*
k=y/x?
actually not necessary in the case of direct variation is it?
(5,25) (10,50)
just pick a point i pick (10,50) slope is second number over the first \[\frac{50}{10}=5\]
lol yal just taught me way more than what my teacher has lol
also note that \[\frac{25}{5}=5\] too
use the points (10,50) and (0,0)
with direct variation you don't use two points it is the second number divided by the first
glad to help, hope it is clear
yes
rate of change, \[\frac{dy}{dx}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}=\frac{50-0}{10-0}=\frac{50}{10}=5\]
Yes thank all of you im not gunna give a medal because all of you helped me understand and i am extremely grateful!!! THANK YOU!!!!!!!!!!!!
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