Please help! Solve (3x^2+13x-10) ÷ (x+5)

Question

campbell_st · Answer

well I'd factor the quadratic equation... then look for a common factor.

anonymous · Answer

@campbell_st i need help solving the whole thing because i dont know how to solve it.

campbell_st · Answer

so you can't factor the quadratic.... forget solving at this stage... the 1st task is factoring...

anonymous · Answer

is it 3x^25 divided by x+5

campbell_st · Answer

here is a lesson if factoring difficult quadratics in the form 

$$ax^2 + bx + c$$

multiply a and c... so in your question its 3 * -10 = -30

now find the factors of -30 that add to 13.... the larger factor is positive and the smaller is negative...

any thoughts.

anonymous · Answer

im sorry i have no idea. i never did these problems bofore

campbell_st · Answer

ok.... so the factors of -30 are 15 and -2

next write the factored form as 

(ax + factor 1)(ax + factor2)
------------------------
                    a

so in your question its 

$$\frac{(3x + 15)(3x -2)}{3}$$

take out common factors in the numerator 

$$\frac{3(x + 5)(3x - 2)}{3}$$

cancel the common factor and its 

$$3x^2 + 13x -10 = (x +5)(3x -2)$$

so now the initial problem becomes 

$$(x + 5)(3x -2) \div(x + 5)~~~or~~~~\frac{(x + 5)(3x -2)}{(x + 5)}$$

now you can get a solution

anonymous · Answer

how do i get the solution?