Question

ques..

Answer 1

\[\int\limits [\frac{d(lnx)}{dx}.\int\limits x^3dx]dx=\int\limits [\frac{1}{x}.\int\limits x^3dx]dx-\int\limits[\int\limits x^2dx]dx\] okay?

Answer 2

sorry theres a equal there instead of minus

Answer 3

I don't think you can cancel the x outside of the integral with the x inside.

\(\dfrac{1}{x}\int x^3dx = \dfrac{1}{x}[\dfrac{x^4}{4}]=\dfrac{x^3}{4}\)

Answer 4

hmm I was having a doubt...thanks