Question

A 1,700 kg car coasts down a hill starting from rest and decreases its height by 22 m over a distance of 110 m of travel. How fast will it be going at the end of the hill, if friction has no effect in slowing its motion?

Answer 1

Hi Welcome to Openstudy!

I think you can use Energy conservation here:
let's see...
Ek= kinetic energy = 1/2mv^2
Ep= potential energy = mgh

given:
m= 1700 kg
vi=0m/s
di = 110 m //decreases by 22 m
vf= ? when df = 0

accdg to the law: Total initial mechanical energy = total Final mechanical energy
\(\sf E_{ki} + E_{pi} = E_{kf} + E_{pi}\\1/2mv_i^2+mgd_i=1/2mv_f^2+mgd_f\\0+mgd_i=1/2mv_f^2+0\\v_f= \sqrt{2gd_i}\)