Question

In a mist, a runner was walking at 2 km/h, a bike passes him in the same direction.
The runner could see the bike for 6 minutes and it was visible to him
upto the distance of 0.6 km. the speed of the bike in km/hr was ?

Answer 1

Lets call relative speed (km/h) of the bike to runner \(v\). And it's real speed \(V\). The relation between this two is: \(v=V-2\). Sincé the bike moved distance 0.6 km in 6/60 = 1/6 hours. It's speed relative to runner, \(v\), was 0.6*6=3.6 km/h. To find it's real speed use the relation above.

Answer 2

\(\large \color{black}{\begin{align} v& =V-2\\
V& =v+2=3.6+2=5.6\quad km/hr\end{align}}\)

unfortunately this is wrong

Answer 3

\(\large \color{black}{\begin{align}
a.) 30\quad \text{km/hr}\hspace{1.5em}\\~\\
b.) 15\quad \text{km/hr}\hspace{1.5em}\\~\\
c.) 20\quad \text{km/hr}\hspace{1.5em}\\~\\
d.) 8\quad \text{km/hr}\hspace{1.5em}\\~\\
\end{align}}\)

Answer 4

rel vel V-2 so 0.6=(V-2)*6/60
so d

Answer 5

haha yep! correct !