Question

find the value of x=1

X = 1 + ____1______ .

2+ ____1______ .

2+ ____1______ .

2+ ____1______ .

2+ …….infinity

Answer 1

It's already the value. :)

Answer 2

sorry I am just try to give it shape.. not sure how to put underline.. so ...

Answer 3

I really can't understand the input.

Answer 4

is this your question ?

\(\large \color{black}{\begin{align} x = 1 + \cfrac{1}{2
+ \cfrac{1}{2
+ \cfrac{1}{2 + \cfrac{1}{2 + \cdots \infty^{+}}}}}
\end{align}}\)

Answer 5

whew!! mathmath333 you have always been my saviour so far

Answer 6

@mathmath 333; I don't know how you are able to write like this but yes this is indeed the question Sir,,

Answer 7

\[\large x = 1+ \dfrac{1}{1+x}\]

Answer 8

ganeshie8's method came from this


\(\large \color{black}{\begin{align} x = 1 + \cfrac{1}{2
+ \cfrac{1}{2
+ \cfrac{1}{2 + \cfrac{1}{2 + \cdots \infty^{+}}}}}\hspace{1.5em}\\~\\
\implies x +1= 2 + \cfrac{1}{2
+ \cfrac{1}{2
+ \cfrac{1}{2 + \cfrac{1}{2 + \cdots \infty^{+}}}}}\hspace{1.5em}\\~\\
\implies x +1= 2 + \cfrac{1}{
x+1}\hspace{1.5em}\\~\\
\implies x = 1 + \cfrac{1}{
x+1}\hspace{1.5em}\\~\\

\end{align}}\)

Answer 9

So the value of x =2?

Answer 10

no u will get the quadratic equation , which will give two values

Answer 11

Yes, sorry.. x=1 is what I get

Answer 12

@ganishe8 this is fast, real fast would like to know who taught you maths

Answer 13

\(\large \color{black}{\begin{align}
x +1= 2 + \dfrac{1}{
x+1}\hspace{1.5em}\\~\\
( x +1)^2= 2(x+1) + 1\hspace{1.5em}\\~\\
( x +1)^2-2(x+1)+1= 2\hspace{1.5em}\\~\\
\left(( x +1)-1\right)^2= 2\hspace{1.5em}\\~\\

x=\pm\sqrt 2
\end{align}}\)

Answer 14

hmmm, yes thanks mathmath333

Answer 15

note that here only \(x=+\sqrt2\) is possible and not

\(x\neq -\sqrt2\)

Answer 16

so the ans is \[\sqrt{2}\] ?

Answer 17

yes