[Reward : Medal, Fan and Friendship :3]
Factorise m^4 - 16 completely using the suitable identity.

Question

[Reward : Medal, Fan and Friendship :3]
Factorise m^4 - 16 completely using the suitable identity.

anonymous · Answer

@ganeshie8 @Iambatman

anonymous · Answer

For this you need to have:
$$\large \color{red}{a^2 - b^2 = (a+b)(a-b)}$$

anonymous · Answer

See, you can rearrange what you are given with like the following:
$$\color{blue}{m^4 = (m^2)^2}$$
$$\color{green}{16 = 4^2}$$

anonymous · Answer

So, now make use of that formula:
$$(\color{blue}{m^2})^2 - (\color{green}{4})^2 = ??$$

anonymous · Answer

So, basically, you are having : $a = m^2$ and $b = 4$.

Just plug in these values of $a$ and $b$ there in that formula and there you go..!!

anonymous · Answer

Do you want to try yourself or just want answer?

anonymous · Answer

Can I have the answer coz Im kinda busy? @eta

anonymous · Answer

Yes, we are aliens here who are totally free to do your homework, right??

Do the problem yourself, I have given sufficient data to solve it, and please try once and if having doubt, then do ask me..

anonymous · Answer

Thanks I guess. -_- @eta

anonymous · Answer

Don't guess, make yourself sure everytime.. :P

anonymous · Answer

Cheese, Fine then Thanks. :P

anonymous · Answer

$\dagger$