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Mathematics 9 Online
OpenStudy (anonymous):

Find the area of the triangle below. Round your answer to the nearest tenth.

OpenStudy (anonymous):

\[A=\frac{ 1 }{ 2 }bh\]

OpenStudy (anonymous):

b is the base, h is the height

OpenStudy (anonymous):

|dw:1425138408891:dw|

OpenStudy (anonymous):

|dw:1425138445804:dw|

OpenStudy (anonymous):

I know the formula But I need to solve the equation by finding the height and solving for area.

OpenStudy (anonymous):

Oh you're right, I see the triangle is 97 degrees now. Tricky question. You shouldn't draw it as a right triangle

OpenStudy (anonymous):

Oh lol, Just saw it.

OpenStudy (anonymous):

So, 15 * 11/ 2

OpenStudy (anonymous):

No you are right. It is more complicated.

OpenStudy (anonymous):

Wait no, The ange is 97

OpenStudy (anonymous):

The triangle has an angle of 97 degrees

OpenStudy (anonymous):

yeah so we need to find the height just like you said

OpenStudy (anonymous):

|dw:1425138581386:dw|

OpenStudy (anonymous):

this picture is more accurate

OpenStudy (anonymous):

Ok

OpenStudy (anonymous):

I would start by trying to find the length of the side that is the hypotenuse for the triangle that has a 7 deg radius.

OpenStudy (anonymous):

But we only have one length.

OpenStudy (anonymous):

|dw:1425138801766:dw|

OpenStudy (anonymous):

is this a new drawing?

OpenStudy (anonymous):

Wait we should find the hypotenuse.

OpenStudy (anonymous):

and yes

OpenStudy (anonymous):

this triangle has to be a 30 - 60 -90

OpenStudy (anonymous):

Ok

OpenStudy (anonymous):

Then we can use the law of sine

OpenStudy (anonymous):

No the law of cosine

OpenStudy (anonymous):

And actually the picture you drew isn't correct since that isn't the triangle height

OpenStudy (anonymous):

Which one?

OpenStudy (anonymous):

|dw:1425139174366:dw| the black line is the height

OpenStudy (anonymous):

Ok.

OpenStudy (anonymous):

let's rexamine the problem now

OpenStudy (anonymous):

But what happens to the angle?

OpenStudy (anonymous):

the angle gets split now

OpenStudy (anonymous):

by how much we dont know yet

OpenStudy (anonymous):

We can solve this very easy with the law of cosines by I'm not sure you need to do that. There could be an easier way

OpenStudy (anonymous):

I think the angle would be split 45 - 52 by analysis.

OpenStudy (anonymous):

Could we use this formula = \[1/2bc \sin A = 1/2ac \sin B = 1/2ab \sin C \]

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