Mathematics
9 Online
OpenStudy (anonymous):
Find the area of the triangle below. Round your answer to the nearest tenth.
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OpenStudy (anonymous):
\[A=\frac{ 1 }{ 2 }bh\]
OpenStudy (anonymous):
b is the base, h is the height
OpenStudy (anonymous):
|dw:1425138408891:dw|
OpenStudy (anonymous):
|dw:1425138445804:dw|
OpenStudy (anonymous):
I know the formula
But I need to solve the equation by finding the height and solving for area.
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OpenStudy (anonymous):
Oh you're right, I see the triangle is 97 degrees now. Tricky question. You shouldn't draw it as a right triangle
OpenStudy (anonymous):
Oh lol, Just saw it.
OpenStudy (anonymous):
So, 15 * 11/ 2
OpenStudy (anonymous):
No you are right. It is more complicated.
OpenStudy (anonymous):
Wait no, The ange is 97
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OpenStudy (anonymous):
The triangle has an angle of 97 degrees
OpenStudy (anonymous):
yeah so we need to find the height just like you said
OpenStudy (anonymous):
|dw:1425138581386:dw|
OpenStudy (anonymous):
this picture is more accurate
OpenStudy (anonymous):
Ok
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OpenStudy (anonymous):
I would start by trying to find the length of the side that is the hypotenuse for the triangle that has a 7 deg radius.
OpenStudy (anonymous):
But we only have one length.
OpenStudy (anonymous):
|dw:1425138801766:dw|
OpenStudy (anonymous):
is this a new drawing?
OpenStudy (anonymous):
Wait we should find the hypotenuse.
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OpenStudy (anonymous):
and yes
OpenStudy (anonymous):
this triangle has to be a 30 - 60 -90
OpenStudy (anonymous):
Ok
OpenStudy (anonymous):
Then we can use the law of sine
OpenStudy (anonymous):
No the law of cosine
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OpenStudy (anonymous):
And actually the picture you drew isn't correct since that isn't the triangle height
OpenStudy (anonymous):
Which one?
OpenStudy (anonymous):
|dw:1425139174366:dw| the black line is the height
OpenStudy (anonymous):
Ok.
OpenStudy (anonymous):
let's rexamine the problem now
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OpenStudy (anonymous):
But what happens to the angle?
OpenStudy (anonymous):
the angle gets split now
OpenStudy (anonymous):
by how much we dont know yet
OpenStudy (anonymous):
We can solve this very easy with the law of cosines by I'm not sure you need to do that. There could be an easier way
OpenStudy (anonymous):
I think the angle would be split 45 - 52 by analysis.
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OpenStudy (anonymous):
Could we use this formula = \[1/2bc \sin A = 1/2ac \sin B = 1/2ab \sin C \]