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If tan A + cot A = 5 find the value of tan^2 A + cot^2 A
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@satellite73
@ParthKohli
@iambatman
\[\tan(A) + \cot(A) = 5 \\ \tan(A) + \frac{1}{\tan(A)} = 5 \\ \tan^2(A) + 1 = 5 \tan(A) \\ \tan^2(A) - 5 \tan(A) +1 = 0\]
Solve this quadratic to find \(\tan(A)\).
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I don't know how to.
@eta
@sleepyhead314 @sleepyjess
@ParthKohli
Just square both sides.
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I am dumb..
Can you explain it in a better way?
\[\tan A + \cot A = 5\]Square both sides.
\[(ta(A) + \cot(A))^2 = 5^2\] now proceed..
25?
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*tan(A)..
@ParthKohli Help me in more questions?
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