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A horizontal safely supports a load P that varies jointly as the product of the width W of the beam and the square of the depth D and inversely as the length L. A beam that has a width of 6 in, depth of 12 in, and length of 4 in can safely support 2,592 lb. Determine the safe load in pounds of a beam made from the same material if the beam is 12 in long. The safe load is?
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@ChloeSmith09 P = K. W.D^2 / L
where K is constant of proportionality. and W,D and L are defined in question.
2592 = K. 6.12.12/4 K=12
now new P= 12.6.12.12/12 Pnew = 884 lbs
this would be the answer
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