A student divided f(x)=3x^3+8x^2+5x-4 by x+2 and found the remainder was r=-6. based on the remainder theorem, what can be concluded about f(x)?
well since the remainder wasn't 0 you can conclude that x+2 is not a ______
think f word
For example the remainder when (x^2-x) is divided by x is 0 but x^2-x can be written as x(x-1) What is x and x-1 called of x^2-x?
idk
Can you complete this sentence: 3 is a _______ of 9
What if I asked you to factor 9? OR write the factors of 9?
3 times 3
ok the factors of (x^2-x) are x and x-1 so dividing (x^2-x) by either one its factors will give you a remainder of 0 just like if you divide 9 by one of its factors you get a remainder of 0
so when we have f(x) divided by d(x) giving us a remainder of 0 then that tells us that d(x) is a __________ of f(x)
and when we don't get a remainder 0 then d(x) is not a __________ of f(x).
it is hard not to get this one since I told you the first letter of the word and I repeated the word a few times
ok I know it's factor. there are 4 choices: a) the point (-2,-6) lies on the graph of f(x) b) the function f(x)3x^3+8x^2+5x-4 has a zero at -6 c) the y-intercept of the graph of f(x)=-6 d) the function f9x)3x^3+8x^2+5x-4 has a zero at -2
oh no that isn't what I was trying to get you to see i was trying to get you to see it isn't a factor
the remainder is not 0 so it (x+2) is not a factor if the remainder was 0 (x+2) is a factor
well you can find the remainder of f(x) divide by (x+2) by simply plugging in -2 into the original function
ok, yes, I know that. which one do you think is the answer out of the 4 I just gave?
So if I tell you f(-2)=remainder=-6 in this case then what could you tell me
For example pretend f(x)=x^2-x dividing it by x-4 gives a remainder of 12 Well that would mean f(4)=12 by remainder theorem
f(x)=y tells a point on f that point being (x,y)
so if have f(4)=12 that means (4,12) on a point on f(x)=x^2-x
do you understand what the answer is yet?
yes, I got it. thank you for your time
Join our real-time social learning platform and learn together with your friends!