3x=2y+10 9y=3x-7
Have you learned "substitution"?
\(\color{red}{3x}=2y+10\) \(9y=\color{red}{3x}-7\) Put the right hand side of the first equation into the red (3x) of the second equation and solve for y, and then x.
I did it 9y=(2y=10)-7 9y=2y+10-7 9y-2y=10-7 7y=3 y=3/7
i need to solve it by addition method
y=3/7 and x=76/21
You can do that too, by adding the two equations together, and cancelling 3x on each side. The rest is the same. BTW, what did you get for X?
and i got struck
Yes, the answer is correct.
Where did you get stuck?
but i can't solve for x
i know answer but i don't know how to do it
Add the two equations together: 3x=2y+10 9y=3x−7 You'll get 9y+3x = 2y+3x+10-7 So by cancelling 3x and isolating y, you get 9y-2y=3 7y=3 y=3/7 The rest is the same.
i don't know how to solve for y because i am really bad at math
Do you mean you don't know how to solve for x?
yes
really i don't know
Put y=3/7 into one of the two equations, say the first one. 3x=2y+10 3x=2(3/7)+10 3x=6/7+10 3x=76/7 x=76/(7*3)=76/21 Please study and make sure you understand all the steps!
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