Question

A sample of a compound of Cl and O reacts with an excess of H2 to give 0.233 g of HCl
and 0.403 g of H2O. Determine the empirical formula of the compound.

Answer 1

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Answer 2

All you need to do here is calculate the moles.

For CL, it is given as 0.233, but the formula mass for HCL is 36.46.

0.233/36.46=0.00639 moles

For O, it is given as 0.403, but the formula mass is 18.02.

0.403/18.02=0.0024 moles

now just divide both by the smallest number

0.00639/0.00639=1
0.0024/0.00639=3.5

you can't have decimals, so multiply both by 2.

Your empirical formula is CL2O7

Answer 3

thanks