Question about the relationship between entropy, gibbs free energy, and enthalpy..
So I know that if a reaction has a negative enthalpy, positive entropy and a negative gibbs free energy, the reaction will be spontaneous at all temperatures. All positive enthalpys, negative entropys, and positive gibbs, the reaction is not spontaneous. But if a reaction has a negative entropy and a negative enthalpy....the reaction supposedly occurs at low temperatures, does it matter what sign the gibbs energy is? Or if a reaction has a positive entropy and enthalpy, the reaction is supposedly occuring at high temperatures, does it also matter what sign it is?
@Somy
@Abhisar
http://chem.wisc.edu/deptfiles/genchem/sstutorial/Text13/Tx131/tx131.html u might want to check this out. the whole page is useful
' When ΔG is negative, a process or chemical reaction proceeds spontaneously in the forward direction. When ΔG is positive, the process proceeds spontaneously in reverse. When ΔG is zero, the process is already in equilibrium, with no net change taking place over time. '
http://chemed.chem.purdue.edu/genchem/topicreview/bp/ch21/gibbs.php all you want to know is here https://www.youtube.com/watch?v=XvuRJuXykyw he'll define each & once u hear it you might conclude their relationship & learn how to do calculation if you dont know :)
the sign of \(\Delta G\) will determine whether the reaction runs in the indicated direction, it is the \(result\) of the \(\Delta H\) and \(\Delta S\), not an additional factor.
Got it, gibbs is based on the temperature on my factors, thanks everyone
no problem :)
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