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What is the number of nitrogen atoms in 60.0g of CO(NH2)2. A 3x10^23 B 6x10^23 C 1.2x10^24 D 2.4x10^24 Double checking @Abhisar @Somy @dtan5457
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\[Number~of~moles=\frac{ 60g }{ 60g~mol^{-1} }\]
\[=1mol\]
\[Number~of~nitrogen~atoms=1mol~\times6\times10^{23}mol^{-1}\]
\[=6\times10^{23}\]
My answer is B
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Am i correct?
@Abhisar
\(\huge \checkmark\)
Thnx @Abhisar :)
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