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Chemistry 13 Online
OpenStudy (anonymous):

What is the number of nitrogen atoms in 60.0g of CO(NH2)2. A 3x10^23 B 6x10^23 C 1.2x10^24 D 2.4x10^24 Double checking @Abhisar @Somy @dtan5457

OpenStudy (anonymous):

\[Number~of~moles=\frac{ 60g }{ 60g~mol^{-1} }\]

OpenStudy (anonymous):

\[=1mol\]

OpenStudy (anonymous):

\[Number~of~nitrogen~atoms=1mol~\times6\times10^{23}mol^{-1}\]

OpenStudy (anonymous):

\[=6\times10^{23}\]

OpenStudy (anonymous):

My answer is B

OpenStudy (anonymous):

Am i correct?

OpenStudy (anonymous):

@Abhisar

OpenStudy (abhisar):

\(\huge \checkmark\)

OpenStudy (anonymous):

Thnx @Abhisar :)

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