Question

If 8.0 L of ethyle glycol, C2H4(OH)2, density = 1.113 g/mL, is placed in an automobile radiator and diluted with 32 L of water, density = 1.0 g/mL, what is the approximate freezing point of the solution?

Answer 1

@shrutipande9 i think its much more harder that the other problems

Answer 2

okay..now for molality of ethyl alcohol we need weight of solute to find moles. so we need to convert liter to kg

Answer 3

using the density?

Answer 4

yeah

Answer 5

water is 32 kg

Answer 6

perfect....actually u need it in grams..so keep it 8904g. and what is the molecular weight of ethyl glycol

Answer 7

62.0678 g/mol

Answer 8

it is 62.07g
so no of moles would be 8904/62.07 right?

Answer 9

yun

Answer 10

yup*

Answer 11

then find moles. then find molality.
then samme \[\Delta Tb = Kb * m\]

Answer 12

MW of ethyl glycol is 62.0678 g/mol

Answer 13

yep

Answer 14

how to get the molality? :D

Answer 15

what is the no of moles u got?

Answer 16

what is the W, in kg?

Answer 17

is it 1 kg?

Answer 18

143.45m

Answer 19

are you there @shrutipande9

Answer 20

sorry internet issues

Answer 21

:D

Answer 22

W in kgs wwould be weight of solvent..which is kgs
now as density of water is 1. 32l of water = 32kg of water

Answer 23

OH! where did u get 1.321?

Answer 24

no no...its a fullstop.:P
density of water is 1
so 32 liters of water= 32 kg of water

Answer 25

yep

Answer 26

how to compute for molality?

Answer 27

what u r doing is perfect..just instead of W write 32 and find Molality

Answer 28

i got m = 123.45m for ethyl gly , and m= 1777.78 m for water

Answer 29

ops, 143.45m for ethyl *

Answer 30

how can we o it now...hmmm?

Answer 31

ok wait wait...

Answer 32

yep

Answer 33

how much did u get by this?

Answer 34

w8 my mistake... haha i get it