Question

Limits question.

Answer 1

The limit of the Capacity of the following complex number using L'hopital rule :

\[\lim_{d \rightarrow \frac{ \pi }{ 2 }} \frac{ \cos(d) + \sin(d)i }{ \sin(d)\cos(d) }\]

Answer 2

wolfram gives does;nt exists

Answer 3

multiply 2 in denom and numerator
sin2d in denom...then use L-hopital

Answer 4

or u can use the fact

\(\large \color{black}{\begin{align} \lim_{d\to\pi/2^{+}}\frac{1}{\cos d}=+\infty\hspace{.33em}\\~\\
\lim_{d\to\pi/2^{-}}\frac{1}{\cos d}=-\infty\hspace{.33em}\\~\\
\end{align}}\)

Answer 5

Tried this before.
2Cos(d) +2 sin(d)i/sin2d
now....

Answer 6

[ 1+ sin(d)i/cos(d) ] / sin(d)
1+ sin(d)i * -inf / sin(d)

Answer 7

(2Cos(d) +2 sin(d)i)/sin2d now use de L'hopital's rule

Answer 8

use it , I failed.

Answer 9

could you write a formula after de L'Hopitals ?

Answer 10

-sin(d) + cos(d)i / 2cos(2d)
= -1 / -1 = 1

Answer 11

correct :)

Answer 12

-2sin(d) + 2cos(d)i, but solution is right

Answer 13

@zarkon ineed your help

Answer 14

But i don't want to solve the derivative

Answer 15

I wanna solve it using this rule sinx/x = 1

Answer 16

uisng*

Answer 17

what a mess