Question

11. Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places.

99% confidence; n = 6500, x = 1950

0.0128
0.0146
0.0083
0.011

Answer 1

@kirbykirby

Answer 2

someone told me this one is D is that true

Answer 3

this is a test right if it is please try figuring out on your own if not I can help

Answer 4

did i say it was?

Answer 5

Hm well

The margin of error is the part we saw before that's after the \(\pm\), so \[z\cdot \sqrt{\frac{p(1-p)}{n}}\]. And well for a 99% confidence level, z=2.58

Answer 6

I didn't say u did did I I was asking u if it is a test !!!!!!!!!!!!!!!!!!!!!!

Answer 7

its not

Answer 8

what p

Answer 9

I said I didn't say it was a test did I

Answer 10

can u type the numbers where they are supposed to be then I"ll solve it

Answer 11

um well \(p=\dfrac{x}{n}\) and \(z=2.58\) which is the z-score

Answer 12

ok i see one sec

Answer 13

wat number is p?

Answer 14

\(p=\dfrac{x}{n}\), they give you x=1950, and n = 6500 :)

Answer 15

then wat goes in for P?

Answer 16

ok I got 0.0146

Answer 17

that's what I got too

Answer 18

12. Provide an appropriate response.

Samples of size n = 900 are randomly selected from the population of numbers (0 through 9) produced by a random-number generator, and the proportion of numbers ≥ 5 is found for each sample. What is the distribution of the sample proportions?

skewed to the right
skewed to the left
not enough information provided
normal (approximately)

Answer 19

\[\ge5\]

Answer 20

usually these are normal

Answer 21

yes it should be approx normal

Answer 22

13. Solve the problem.

The following confidence interval is obtained for a population proportion, p: (0.707, 0.745). Use these confidence interval limits to find the margin of error, E.

0.017
0.020
0.038
0.019

Answer 23

So I explain the margin of error previously and you know the formula for the confidence interval. So.. you can represent the confidence interval as \(C.I = p\pm E\)

Answer 24

The lower limit of the confidence interval would be \(p - E\)
the upper limit would be \(p+E\)

So:
\(0.707=p-E\)
\(0.745=p+E\)

Answer 25

so basically it's a system of equations with 2 unknowns. You just need to solve for E :)

Answer 26

0.019

Answer 27

@kirbykirby

Answer 28

@mathmate

Answer 29

is this right

Answer 30

ya I got that =]

Answer 31

last one ok