Question

solve this logarithmic equation!

Answer 1

\[\log_{10} (9x ^{2}-\log(x) = 2\]

Answer 2

should be (9x^2)

Answer 3

and if the second log is also base 10, what is the difference between 2 logs in same base?

you can combine them.

Answer 4

Hint: \(\log_{10}(10^2) = 2\)

Answer 5

And \(log_{10}(a) - log_{10}(b) = log_{10}(a/b)\)

Answer 6

honestly that's not making much sense to me. this isn't my strong suit

Answer 7

you have this equation right?
\[\log_{10}(9x^2) - \log_{10}(x)=2\]

Answer 8

yes

Answer 9

Ok, from what i wrote above, we have:
\[\log_{10}(\frac{9x^2}{x}) = \log_{10}(9x) = 2\]

Answer 10

But,
\[\log_{10}(9x) = \log_{10}(10^2)\]
That means that:
\[9x=100 \Rightarrow x = 100/9\]

Answer 11

okay