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Mathematics 19 Online
OpenStudy (anonymous):

Please Help! I'll give a medal! I know I already posted this question but I need someone to explain it to me better. Subtract (x+2/2x)-(x/x+3) Discuss and identify any possible restrictions that exist with (or in) the resulting rational expression.

OpenStudy (loser66):

\[\frac{x+2}{2x}-\frac{x}{x+3}\] right?

OpenStudy (anonymous):

yes

OpenStudy (loser66):

first off, all your denominator must be \(\neq 0\) , those are restriction, hence \(x\neq 0\) and \(x+3\neq 0\) or \(x\neq -3\) ok?

OpenStudy (loser66):

I ate all s after denominator and restriction, hehehe... they should be denominators and restrictions.

OpenStudy (anonymous):

Huh? I am confused

OpenStudy (loser66):

why? that's the rule for a fraction has some meaning.

OpenStudy (anonymous):

All the threes and zeros and xs look like they are all combined so it is confusing to me. Can we just solve the thing first, then look at the restrictions?

OpenStudy (loser66):

nope, restriction first ALWAYS

OpenStudy (loser66):

You must have restrictions before solving, so that if your solutions "violate" the restrictions, you get rid them off.

OpenStudy (anonymous):

okay can you explain the restrictions a little more and explain how your getting them in words, I understand things better that way

OpenStudy (loser66):

if you have a fraction and the variable on the denominator, then the denominator must be not 0 . That is the way you find out the restriction

OpenStudy (loser66):

|dw:1425246088504:dw|

OpenStudy (anonymous):

okay

OpenStudy (loser66):

|dw:1425246121411:dw|

OpenStudy (loser66):

those are examples of restrictions, not your problem

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