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Mathematics 14 Online
OpenStudy (anonymous):

Solve for x. Picture will be in comments, explain how to get answer don't just give it too me.

OpenStudy (tkhunny):

Have you considered the sine or cosine?

OpenStudy (anonymous):

I know that's how you're supposed to do it but I don't know how to use them.

OpenStudy (anonymous):

Quote: "SOHCAHTOA" The S, the C, and the T stand for -> Sin, cos, and tan, and it goes in order Sine-> opposite/hypotenuse Cosine-> Adjacent/Hypotenuse Tangent-> Opposite / Adjacent

OpenStudy (anonymous):

towards 28 degrees you have sine 28 degrees, and that is opposite/hypotenuse You are given the opposite, (50) and need to find the hypotenuse (x) So you just plug in sin 28 = 50/X

OpenStudy (anonymous):

So I would use Sine? Because the side i have is the opposite and the one I need is the hypotenuse?

OpenStudy (anonymous):

yes! u got it :)

OpenStudy (tkhunny):

Or the cosine. You have enough information to use either. \(\sin(28º) = \cos(62º)\)

OpenStudy (anonymous):

I'm not compleltey sure, but 106.502 is what I got

OpenStudy (tkhunny):

Did you try setting up the ratio and being sure? \(\sin(28º) = \cos(62º) = \dfrac{50}{x}\)

OpenStudy (anonymous):

I'm not sure how to do it

OpenStudy (anonymous):

the sin(28)= 0.469 and so does cos(62)

OpenStudy (tkhunny):

You will need a calculator to calculate the sine or the cosine.

OpenStudy (tkhunny):

Well, there you go. Add that to the ratio equation and solve for x.

OpenStudy (tkhunny):

It had better not say either of those. You should start with 50/x, not with x/50. Also, whoever requires you to "swap sides" like that needs to take a chill pill. No one should care about something like that.

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